If sec A = 15/7 and …
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Posted by Kumar ... 1 year, 10 months ago
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Preeti Dabral 1 year, 10 months ago
sec A {tex}= \frac { 15 } { 7 }{/tex}
{tex}\Rightarrow{/tex} sec(90° - B) {tex}= \frac { 15 } { 7 }{/tex} [{tex}\because{/tex} A + B = 90° {tex}\Rightarrow{/tex} A = 90° - B]
{tex}\Rightarrow{/tex} cosec B {tex}= \frac { 15 } { 7 }{/tex} [{tex}\because{/tex} sec (90° - {tex}\theta{/tex}) = cosec {tex}\theta{/tex})
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