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A small candle 2.5 cm in …

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A small candle 2.5 cm in size is placed at 27 in front of a concave mirrir of radius of curvature 36 cm at what distance from the mirror should a screen be placed in a order to obtain a sharp image ? Describe the nature and size of the image if the candle is moved closer to the mirror , how would the screen have to be moved ?

Posted by Deepu Kumar Yadav 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Anjan Karthi 2 years, 2 months ago

h = 2.5 cm. u = - 27 cm. R = 2f = - 36 cm. Therefore, according to mirror formula, 1/f = 1/v + 1/u. 1/v = 1/f - 1/u = 1/18 - 1/27 = - 9 / 18 × 27 = - 1 / 54. v = - 54 cm. Magnification m = -v/u = 54/-27 = - 2 = h'/h. h' = mh = - 2 × 2.5 = -5 cm. So, the image is real, inverted and enlarged and is formed at a distance greater than R in front of the mirror. If the candle is brought closer to the mirror, then the screen should be moved far away from the mirror.

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