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An alpha particle is accelerated through …

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An alpha particle is accelerated through a potential difference of 10kV and moves along the x-axis. It enters in a region of uniform magnetic field B= 2 × 10-3 T acting along the Y-axis. Find the radius of its path

Posted by Aayush Singh 2 years, 2 months ago

CBSE > Class 12 > Physics

1 answers

Preeti Dabral 2 years, 2 months ago

r=√(2mqV) / qB

as given alpha particle q=2e=2×1.6×10^-19

V=10^4V

m=6.4×10^-27kg

B=2×10^-3T

r=√(2 × 6.4×10^-27 × 2× 1.6×10^-19 × 10^4) /1.6×10^-19 × 2×10^-3

=√(4096×10^-44) / 64 × 10^-23

=(64 × 10^-22) / (64 × 10^-23)

=10

therefore radius is 10m

1Thank You

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