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A piece of wire of resistance …

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A piece of wire of resistance 20 ohm is drawn out so that it's length is increased to twice it's original length.calculate the resistance of wire in the new situation?

Posted by Madhu Singh 3 years ago

CBSE > Class 10 > Science

5 answers

Madhu Singh 3 years ago

If the original length and the cross-sectional area of the wire are landA, respectively, then R=ρlA or 20Ω=ρlA. When the length becomes 2l and cross-sectional area is A/2. Rnew=ρ(2l)A/2=4(ρl/A)=4(20Ω)=80Ω

1Thank You

Xyz Xyz 3 years ago

Answer is 80ohm

2Thank You

Akshita Agrawal 3 years ago

Heyyy..... Can u give explanation of ur answer... Bcz I think the answer is 80 ohm

2Thank You

Krishna Patel Patel 3 years ago

Hello

1Thank You

Sukesh Kumar 3 years ago

10 ohm

1Thank You

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