A solid metallic object is shaped …
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Preeti Dabral 1 year, 11 months ago
According to the question,
Radius of the cones= r
Height of the upper cone= h
Height of the lower cone= H
Volume of the upper cone {tex}= \frac { 1 } { 3 } \pi r ^ { 2 } h{/tex}
Volume of the lower cone {tex}= \frac { 1 } { 3 } \pi r ^ { 2 } H{/tex}
Total volume of both the cones {tex}= \frac { 1 } { 3 } \pi r ^ { 2 } h + \frac { 1 } { 3 } \pi r ^ { 2 } H{/tex}
{tex}= \frac { 1 } { 3 } \pi r ^ { 2 } ( h + H ){/tex}
The quantity of water displaced by the cones = The total volume of both the cones
therefore,
The quantity of water displaced will be {tex}\frac { 1 } { 3 } \pi r ^ { 2 } ( h + H ) \text { units } ^ { 3 }{/tex}
3Thank You