A solid metallic object is shaped …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Parinith Gowda Ms 2 months, 1 week ago
- 1 answers
Posted by Hari Anand 4 months, 4 weeks ago
- 0 answers
Posted by Sahil Sahil 1 year, 3 months ago
- 2 answers
Posted by Vanshika Bhatnagar 1 year, 3 months ago
- 2 answers
Posted by Parinith Gowda Ms 2 months, 1 week ago
- 0 answers
Posted by Lakshay Kumar 11 months, 2 weeks ago
- 0 answers
Posted by Kanika . 2 months, 4 weeks ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Preeti Dabral 2 years, 10 months ago
According to the question,
Radius of the cones= r
Height of the upper cone= h
Height of the lower cone= H
Volume of the upper cone {tex}= \frac { 1 } { 3 } \pi r ^ { 2 } h{/tex}
Volume of the lower cone {tex}= \frac { 1 } { 3 } \pi r ^ { 2 } H{/tex}
Total volume of both the cones {tex}= \frac { 1 } { 3 } \pi r ^ { 2 } h + \frac { 1 } { 3 } \pi r ^ { 2 } H{/tex}
{tex}= \frac { 1 } { 3 } \pi r ^ { 2 } ( h + H ){/tex}
The quantity of water displaced by the cones = The total volume of both the cones
therefore,
The quantity of water displaced will be {tex}\frac { 1 } { 3 } \pi r ^ { 2 } ( h + H ) \text { units } ^ { 3 }{/tex}
3Thank You