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A solid metallic object is shaped like a double cone as shown in the figure.Radius of base of both cones is same but their heights are different.If this cone is immersed in water,find the quantity of water it will displace.

Posted by Shanu Yadav 2 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Preeti Dabral 2 years, 4 months ago

According to the question,
Radius of the cones= r
Height of the upper cone= h
Height of the lower cone= H
Volume of the upper cone $= \frac { 1 } { 3 } \pi r ^ { 2 } h$
Volume of the lower cone $= \frac { 1 } { 3 } \pi r ^ { 2 } H$
Total volume of both the cones $= \frac { 1 } { 3 } \pi r ^ { 2 } h + \frac { 1 } { 3 } \pi r ^ { 2 } H$
$= \frac { 1 } { 3 } \pi r ^ { 2 } ( h + H )$
The quantity of water displaced by the cones = The total volume of both the cones
therefore,
The quantity of water displaced will be $\frac { 1 } { 3 } \pi r ^ { 2 } ( h + H ) \text { units } ^ { 3 }$

3Thank You

Shanu Yadav 2 years, 4 months ago

Thanks

2Thank You

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