tan(x+y)/cot(x-y) = sin²x -sin²y
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Preeti Dabral 1 year, 10 months ago
Take LHS
{tex}=\frac{\tan (x+y)}{\cot (x-y)}=\frac{\sin (x+y)}{\cos (x+y)} \frac{\sin (x-y)}{\cos (x-y)}{/tex}
{tex}=\frac{\sin ^{2} x-\sin ^{2} y}{\cos ^{2} x-\sin ^{2} y}=R H S{/tex}
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