((sinA-sinB)/(cosA+cosB))+((cosA-cosB)/(sinA+sinB))

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Posted by Kirti Rane 2 years, 10 months ago
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Preeti Dabral 2 years, 10 months ago
{tex}\begin{aligned} & \text { LHS }=\frac{\sin A-\sin B}{\cos A+\cos B}+\frac{\cos A-\cos B}{\sin A+\sin B} \\ & =\frac{\sin ^2 A-\sin ^2 B+\cos ^2 A-\cos ^2 B}{(\cos A+\cos B)(\sin A+\sin B)} \\ & =\frac{\left(\sin ^2 A+\cos ^2 A\right)-\left(\sin ^2 B+\cos ^2 B\right)}{(\cos A+\cos B)(\sin A+\sin B)} \\ & =(\cos A+\cos B)(\sin A+\sin B) \\ & =0=\text { RHS } \end{aligned}{/tex}
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