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((sinA-sinB)/(cosA+cosB))+((cosA-cosB)/(sinA+sinB))

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((sinA-sinB)/(cosA+cosB))+((cosA-cosB)/(sinA+sinB))
  • 1 answers

Preeti Dabral 2 years, 3 months ago

 LHS =sinAsinBcosA+cosB+cosAcosBsinA+sinB=sin2Asin2B+cos2Acos2B(cosA+cosB)(sinA+sinB)=(sin2A+cos2A)(sin2B+cos2B)(cosA+cosB)(sinA+sinB)=(cosA+cosB)(sinA+sinB)=0= RHS 

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