((sinA-sinB)/(cosA+cosB))+((cosA-cosB)/(sinA+sinB))
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Preeti Dabral 2 years, 3 months ago
LHS =sinA−sinBcosA+cosB+cosA−cosBsinA+sinB=sin2A−sin2B+cos2A−cos2B(cosA+cosB)(sinA+sinB)=(sin2A+cos2A)−(sin2B+cos2B)(cosA+cosB)(sinA+sinB)=(cosA+cosB)(sinA+sinB)=0= RHS
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