In what ratio does the point …
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Preeti Dabral 1 year, 11 months ago
Let (-4, 6) divide AB internally in the ratio k:1. Using the section formula, we get
{tex}( - 4,6 ) = \left( \frac { 3 k - 6 } { k + 1 } , \frac { - 8 k + 10 } { k + 1 } \right){/tex}
So, {tex}- 4 = \frac { 3 k - 6 } { k + 1 }{/tex}
i.e., -4k - 4 = 3k - 6
i.e., 7k = 2
i.e., k:1 = 2:7
The same can be checked for the y-coordinate also.
Therefore, the ratio in which the point (-4,6) divides the line segment AB is 2: 7.
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