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Water flows through a horizontal pipe line of varying cross section at the rate of 0.2m³/sec. Calculate the velocity of water at a point where the area of cross section of pipe is 0.02 m ².

Posted by Shanika Sharma 2 years, 6 months ago

CBSE > Class 11 > Physics

1 answers

Preeti Dabral 2 years, 6 months ago

$\begin{aligned} & v=\frac{\text { Rate of flow }}{a} \\ & \text { Rate of flow }=0.2 \mathrm{~m}^3 \mathrm{~s}^{-1} a= \\ & v=\frac{0.2 \mathrm{~m}^s \mathrm{~s}^{-1}}{0.02 \mathrm{~m}^2}=10 \mathrm{~ms}^{-1} \end{aligned}$

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