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If 4m+8,2m²+3m+6 & 3m² + 4m …

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If 4m+8,2m²+3m+6 & 3m² + 4m +4 are 3 concecutive terms of an AP. Find m.

Posted by Karuna Karuna 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajeev Malhotra 7 years, 5 months ago

First term = 4m+8

Second term = $2m^2+3m+6$

Third term = $3m^2+4m+4$

Common Difference d = second term - first term

d = $(2m^2+3m+6) - (4m+8)$

d = $2m^2-m-2$

Common Difference = third term - second term

d = $(3m^2+4m+4)-(2m^2+3m+6)$

d = $m^2+m-2$

So,

$2m^2-m-2 = m^2+m-2$

$m^2-2m=0$

m(m-2)= 0

This gives m= 0 and m-2=0

m=0 or m=2

0Thank You

ANSWER

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CBSE > Class 10 > Mathematics