16x²—10/x=27

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Naveen Gupta 6 years, 5 months ago
- 1 answers
Related Questions
Posted by Kanika . 1 month ago
- 1 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 6 years, 5 months ago
We have, {tex}16x - \frac{{10}}{x} = 27{/tex}
{tex}\Rightarrow \frac{{16{x^2} - 10}}{x} = 27{/tex}
{tex}\Rightarrow{/tex} 16x2 - 10 = 27x
{tex}\Rightarrow{/tex} 16x2 - 27x - 10 = 0
{tex}\Rightarrow{/tex} 16x2 - 32x + 5x - 10 = 0
{tex}\Rightarrow{/tex} 16x(x - 2) + 5(x - 2) = 0
{tex}\Rightarrow{/tex} (16x + 5)(x - 2) = 0
{tex}\Rightarrow{/tex} (16x + 5) = 0 or (x - 2) = 0
{tex}\Rightarrow x = - \frac{{ 5}}{{16}}{/tex} or, x = 2
Hence, the roots of given quadratic equation are 2 and {tex}-\frac{{5}}{16}{/tex}
0Thank You