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16x²—10/x=27

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16x²—10/x=27
  • 1 answers

Sia ? 6 years, 5 months ago

We have, {tex}16x - \frac{{10}}{x} = 27{/tex}
{tex}\Rightarrow \frac{{16{x^2} - 10}}{x} = 27{/tex}
{tex}\Rightarrow{/tex} 16x2 - 10 = 27x
{tex}\Rightarrow{/tex} 16x2 - 27x - 10 = 0
{tex}\Rightarrow{/tex} 16x2 - 32x + 5x - 10 = 0
{tex}\Rightarrow{/tex} 16x(x - 2) + 5(x - 2) = 0
{tex}\Rightarrow{/tex} (16x + 5)(x - 2) = 0
{tex}\Rightarrow{/tex} (16x + 5) = 0 or (x - 2) = 0
{tex}\Rightarrow x = - \frac{{ 5}}{{16}}{/tex} or, x = 2

Hence, the roots of given quadratic equation are 2 and {tex}-\frac{{5}}{16}{/tex}

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