16x²—10/x=27
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Sia ? 5 years, 11 months ago
We have, 16x−10x=27
⇒16x2−10x=27
⇒ 16x2 - 10 = 27x
⇒ 16x2 - 27x - 10 = 0
⇒ 16x2 - 32x + 5x - 10 = 0
⇒ 16x(x - 2) + 5(x - 2) = 0
⇒ (16x + 5)(x - 2) = 0
⇒ (16x + 5) = 0 or (x - 2) = 0
⇒x=−516 or, x = 2
Hence, the roots of given quadratic equation are 2 and −516
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