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The resistance of an electric wire …

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The resistance of an electric wire of an alloy is 10 ohm . If the thickness of wire is 0.001 metre and length is 1metre .Find its resistivity
  • 2 answers

Preeti Dabral 3 years, 1 month ago

Resistance (R) = 10 Ω

Length (L) = 1 m

Diameter (D) = 0.001 m (mentioned as thickness)

The resistivity of an Electric Wire is given by the equation:

                             R = ρ * (L / A)            

Resistivity is measured in Ω.m                  

Where, ρ is the resistivity of the wire

            R is the resistance of the wire

            L is the length of the wire

            A is the area of cross section of the wire.

The equation is rearranged as

                                     ρ = R * (A / L)     ; where A = π r^2  … (π = 3.14)

Substituting the values,

A = 3.14 (0.0005)^2     …………D = r / 2 ; 0.001 / 2 = 0.0005

  = 0.000000785 = 0.785 * 10^-6

ρ = 10 / (0.785 * 10^-6)  

ρ = 0.785 * 10^-5 Ω.m 

Pravesh Mittal 3 years, 1 month ago

Your answer is write
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