The resistance of an electric wire …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Ansh Preet 10 months, 2 weeks ago
- 1 answers
Posted by Tushar Sharma 1 year, 5 months ago
- 2 answers
Posted by Harshita Tondey 1 year, 5 months ago
- 3 answers
Posted by Aadarsh Tripathi 1 year, 5 months ago
- 2 answers
Posted by Pandey Ji 6 months ago
- 0 answers
Posted by Surya Kumar 1 year, 5 months ago
- 1 answers
Posted by Rani Alan 1 year, 5 months ago
- 1 answers
Posted by Harshal Patil 10 months, 2 weeks ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Preeti Dabral 3 years, 1 month ago
Resistance (R) = 10 Ω
Length (L) = 1 m
Diameter (D) = 0.001 m (mentioned as thickness)
The resistivity of an Electric Wire is given by the equation:
R = ρ * (L / A)
Resistivity is measured in Ω.m
Where, ρ is the resistivity of the wire
R is the resistance of the wire
L is the length of the wire
A is the area of cross section of the wire.
The equation is rearranged as
ρ = R * (A / L) ; where A = π r^2 … (π = 3.14)
Substituting the values,
A = 3.14 (0.0005)^2 …………D = r / 2 ; 0.001 / 2 = 0.0005
= 0.000000785 = 0.785 * 10^-6
ρ = 10 / (0.785 * 10^-6)
ρ = 0.785 * 10^-5 Ω.m
3Thank You