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In the given figure dE parallel …

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In the given figure dE parallel BC and AD/DB=3/5 IF AC=5.6 the AE IS

    • Posted by Rahul Raj 2 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Preeti Dabral 2 years, 3 months ago

    Given in triangle ABC And triangle ADE BC || DE
    Also AD/DB = 3/5,AC = 5.6

    To find AE
    In trinagle ABC And ADE
    AD/BD = AE /EC. ----EQ 1........ ( By basic proportionality theorem....)

    Doing reciprocal both sides we get
    BD/AD = EC/AE

    On adding 1 both sides we get,
    BD + AD/AD = EC + AE/
    = AB/AD = AC/AE
    = 8/3 = 5.6/AE
    = AE = 3 × 5.6/8
    = AE = 2.1 cm Ans..

    Hope it will be helpful 

    0Thank You

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