X log 2x
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Preeti Dabral 2 years, 4 months ago
∫xlog2xdx
=∫(log2x)xdx
=(log2x)∫xdx−∫[ddxlog2x∫xdx]dx
[Applying product rule]
=(log2x)x22−∫12x.2.x22dx
=12x2log2x−12∫xdx
=12x2log2x−12x22+c
=x22log2x−x24+c
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