How does the angle of minimum …
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Preeti Dabral 2 years, 9 months ago
Given {tex}^a{\mu _g} = 1.5{/tex} and {tex}^a{\mu _w} = 1.3{/tex}
As, {tex}\delta = (\mu - 1)A{/tex}
For deviation in air, {tex}\mu = \frac{{{\mu _g}}}{{{\mu _a}}} = \frac{{1.5}}{1} = 1.50{/tex}
{tex}\therefore \delta = (1.5 - 1) \times 60^\circ{/tex} = 30°
For deviation in water, {tex}\mu = \frac{{{\mu _g}}}{{{\mu _w}}} = \frac{{1.5}}{{1.3}} = 1.15{/tex}
{tex}\therefore \delta = (1.15 - 1) \times 60^\circ {/tex} = 9°
Therefore, the angle of deviation is decreased.
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