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Find the largest number which which …

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Find the largest number which which divides 615 and 963 leaving remainder 6 in each case.

    • Posted by Gaurav Yadav 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    The required number when divides 615 and 963, leaves remainder 6, this means 615 - 6 = 609 and 963 - 6 = 957 are completely divisible by the number.
    Therefore,
    The required number = H.C.F. of 609 and 957.
    By applying Euclid’s division lemma
    957 = 609 {tex}\times{/tex} 1+ 348
    609 = 348 {tex}\times{/tex} 1 + 261
    348 = 216 {tex}\times{/tex} 1 + 87
    261 = 87 {tex}\times{/tex} 3 + 0.
    Therefore, H.C.F. of 957 and 609 is = 87.
    Hence, the largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

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