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SinA + CosA = √2 Then, …

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SinA + CosA = √2 Then, tanA + CotA= ?

Posted by Iron Man 3 years, 2 months ago

CBSE > Class 10 > Science

3 answers

K.Haniskha💖💖🥰 Kandi☺️ 3 years, 2 months ago

2 is the correct answer

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Student Student 3 years, 2 months ago

0Thank You

Shreya Gupta 3 years, 2 months ago

SinA=√2 - cosA Perpendicular =√2 - cosA Hypotenuse = 1 H^2=P^2+B^2 1^2=(√2 - cosA)^2+ B^2 1=√2^2+CosA^2 - 2×√2×CosA + B^2 1=2+cos^2A - 2√2cosA + B^2 -1=cos^2A - 2√2cosA+ B^2 B^2=-1- cos^2A + 2√2cosAB B=√(-1- cos^2A + 2√2cosAB) tanA + CotA= ? TanA=P/B= √2 - cosA/√(-1- cos^2A + 2√2cosAB) CotA=B/P √(-1- cos^2A + 2√2cosAB)/√2 - cosA tanA + CotA= ? √2 - cosA/√(-1- cos^2A + 2√2cosAB) + √(-1- cos^2A + 2√2cosAB)/√2 - cosA

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CBSE > Class 10 > Science