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If ad not equal to bc …

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If ad not equal to bc then prve that the equation (a square +b square)x suare +2(ac+bd)x +c suare +d sqiare)=0

Posted by Lucky Yadav 2 years, 1 month ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Yadav Yt 2 years, 1 month ago

Discriminant, D=4(ac+bd) 2 −4(a 2 +b 2 )(c 2 +d 2 ) D=4[(ac+bd) 2 −(a 2 +b 2 )(c 2 +d 2 )] D=4[a 2 c 2 +b 2 d 2 +2acbd−a 2 c 2 −a 2 d 2 −b 2 c 2 −b 2 d 2 ] D=4[2acbd−a 2 d 2 −b 2 c 2 ] D=−4[a 2 d 2 +b 2 c 2 −2adbc] D=−4(ad−bc) 2 We have, ad  =bc Therefore, ad−bc  =0 (ad−bc) 2 >0 −4(ad−bc) 2 <0 D<0 Hence, the given equation has no real roots.

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