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Find the perimeter of triangle with vertices (0,4)(0,0)and (3,0)

Posted by Akash Kumar 8 years ago

CBSE > Class 10 > Mathematics

1 answers

Rajeev Malhotra 8 years ago

let the three vertices of a triangle be A(0,4) , B (0,0) and C (3,0).

To find perimeter of a triangle , we have to find the length of sides AB, BC and AC.

Length of AB ={tex}√(0-0)^2+(4-0)^2{/tex}

AB = {tex}√(0)^2+(4)^2{/tex}

AB = {tex}√0+16{/tex}

AB= {tex}√16{/tex}

AB=4

Similarly ,Length of BC = {tex}√(3-0)^2+(0-0)^2{/tex}

BC= √9

BC=3

Length of AC = √({tex}0-3)^2+(4-0)^2{/tex}

AC= √{tex}(3)^2+(4)^2{/tex}

AC = {tex}√9+16 {/tex}

AC = √25

AC= 5

So, perimeter = Sumof lengths of AB, BC and AC

perimeter = AB+BC+AC

perimeter = 4+3+5

perimeter = 12

2Thank You

ANSWER

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