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[29 - (-2) {6 - (7 …

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[29 - (-2) {6 - (7 - 3)}] ÷ [3 × {5 + (-3) × (-2)}]
  • 1 answers

Sahil Thakur 2 years, 3 months ago

In the given question, [29 (2) {6 (73)}] [3x {5+ (-3) × (-2)}] = [29 (-2) (64}] [3 × (5+ 6}] = [29 (2) × 2] + [3 × 11] = = [29+4]÷33 = 3333 =1
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