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A stone is released from top …

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A stone is released from top of the tower of height 19.6 m.Calculate its final velocity before reaching the ground

    • Posted by Thanujkumar Radhakrishnan 2 years, 3 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Isha Nia 2 years, 3 months ago

    Here, Initial velocity u=0 final velocity v=? (to be calculated ) Acceleration due to gravity g=9.8m/s2 Height = 19.6 m V²= u²+2gh = 0²+2(9.8)(19.6) = 19.6(19.6) = (19.6)² V = 19.6m/s

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