No products in the cart.

the roots of the equation x^2+(p+2)x+2p=0 …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

the roots of the equation x^2+(p+2)x+2p=0 are distinct integers when
  • 1 answers

Dharmendra Kumar 7 years, 10 months ago

x2+(p+2)x+2p=0

On comparing with ax2+bx+c=0 we get

a=1  b=p+2    c=2p

Now since roots of the given quadratic equation are distinct integer.

Therefore, Discriminent D=b2-4ac  > 0

                                     (p+2)2-4×1×2p > 0

                                 p2+2×p×2+22 -8p > 0

                                           p2+4p+4-8p > 0

                                                p2 -4p +4 > 0

                                              p2-2p-2p+4 > 0

                                            p(p-2)-2(p-2) > 0

                                                 (p-2)(p-2)  > 0

                                                        (p-2)2 > 0

                                                          p-2   > 0

                                                               p > 2

So roots of the given quadratic eq. is distinct integer if p>2.

http://mycbseguide.com/examin8/

Related Questions

Express the complex number i-39
  • 0 answers
2nC2:nC3=33:10
  • 0 answers
Ch 1 ke questions
  • 1 answers
(3+i)x + (1-2i) y +7i =0
  • 1 answers
Square of 169
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App