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A particle is thrown with velocity …

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A particle is thrown with velocity u making an angle theta
  • 1 answers

Tanushree Mukherjee 2 years, 4 months ago

times taken to reach P is 1s therefore v2=u2+2aS v2=u2cos2θ−2gh let the distance from P to reach at the top be x v2=u2+2as 0=u2cos2θ−2gh−2gx x=2gu2cos2θ​−h time taken is v=u+at 0=ucosθ−g−gt t=gucosθ​−1 time taken to reach top from P is 1s 2g=ucosθ maximum height H=2gu2cos2θ​ as the verical component is ucosθ therefore H=2g(2g)2​=2g=19.6m
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