The calorie is a unit of …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by M D 3 months, 4 weeks ago
- 1 answers
Posted by Nekita Baraily 4 months ago
- 2 answers
Posted by Mohammed Javith 4 months, 1 week ago
- 0 answers
Posted by Pankaj Tripathi 4 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Preeti Dabral 1 year, 10 months ago
The dimensional formula of energy or heat = u = [ ML2T-2 ].
Assume that, M1, L1, T1 and M2, L2, T2 are the units of mass, length and time in given two systems.
{tex}\therefore{/tex} M1 = 1 kg, M2 = {tex}\alpha{/tex} kg
L1 = 1 m, L2 = {tex}\beta{/tex} m
T1 = 1 s, T2 = {tex}\gamma{/tex} s
n1 and n2 are the magnitudes of heat or energy of system one and system two respectively.
For a given physical quantity, the product of its magnitude and unit is always constant.
n1u1 = n2u2
or {tex}n _ { 2 } = n _ { 1 } \frac { u _ { 1 } } { u _ { 2 } } = 4.2 \times \frac { \left[ \mathrm { M } _ { 1 } \mathrm { L } _ { 1 } ^ { 2 } \mathrm { T } _ { 1 } ^ { - 2 } \right] } { \left[ \mathrm { M } _ { 2 } \mathrm { L } _ { 2 } ^ { 2 } \mathrm { T } _ { 2 } ^ { - 2 } \right] }{/tex}
{tex}= 4.2 \left[ \frac { \mathrm { M } _ { 1 } } { \mathrm { M } _ { 2 } } \right] \times \left[ \frac { \mathrm { L } _ { 1 } } { \mathrm { L } _ { 2 } } \right] ^ { 2 } \times \left[ \frac { \mathrm { T } _ { 1 } } { \mathrm { T } _ { 2 } } \right] ^ { - 2 }{/tex}
{tex}= 4.2 \left[ \frac { 1 } { \alpha } \right] \times \left[ \frac { 1 } { \beta } \right] ^ { 2 } \times \left[ \frac { 1 } { \gamma } \right] ^ { - 2 }{/tex}
n2 = 4.2{tex}\alpha ^ { - 1 } \beta ^ { - 2 } \gamma ^ { 2 }{/tex} new unit
Therefore, 1 cal = {tex}4.2 \alpha ^ { - 1 } \beta ^ { - 2 } \gamma ^ { 2 }{/tex} new unit
0Thank You