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Prove that : tanθ+sinθ/tanθ-sinθ​=secθ+1/secθ-1​

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Prove that : tanθ+sinθ/tanθ-sinθ​=secθ+1/secθ-1​
  • 1 answers

Student Life 3 years, 6 months ago

(tanΘ + sinΘ)/(tanΘ - sinΘ) = [(sinΘ/cosΘ + sinΘ)] / [sinΘ/cosΘ - sinΘ] = sinΘ(1/cosΘ + 1) / sinΘ(1/cosΘ - 1) = sinΘ(secΘ + 1) / sinΘ)(secΘ - 1) = (secΘ + 1) / (sec Θ - 1) This is the only way the answer can be typed. Hope u understand.
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