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Factorise 2) x^3 - 3x^2 - …

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Factorise 2) x^3 - 3x^2 - 9x - 5

    • Posted by Neha Dandyan 2 years, 4 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Vishal Rawat 2 years, 4 months ago

    First we find all the factors of the constant term in the polynomial which is 5 here, All factors of 5 are ±1,±5. Then by Remainder theorem we find that x-5 is a factor of p(x). On dividing p(x) by x-5 we get a quotient q(x) = x^2-2x+1. On factorising q(x) we get other two factors (x-1)(x-1). So all the factors of p(x) are (x-5),(x-1) and (x-1).

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