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If One zero of a polynomial …

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If One zero of a polynomial (k+1)x2-5x+5 is multiplicative inverse of other then find the zeros of kx 2-3kx+9, where k is constant.
  • 1 answers

Sana Parveen 6 years, 9 months ago

a = k+1
b = -5
c = 5
Given that,
α = α
β = 1/α
Then,
αβ = c/a
α × 1/α = 5/k+1
By substituting,
1 = 5/k+1
1(k+1) = 5
k+1 = 5
k = 5 - 1
k = 4

Then,
kx^2-3kx+9 = 4x^2 - 3×4×x + 9
= 4x^2 - 12x + 9

4x^2-12x+9 = 4x^2 - 6x - 6x + 9
= 2x(2x-3)-3(2x-3)
= (2x - 3)(2x - 3)

2x - 3 = 0
x = 3/2
= 1.5

ie; α = 1.5
β = 1.5

1.5 and 1.5 are zeros of the polynomial kx^2 - 12x + 9




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