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In the adjoining figure a circle inscribed in a triangle ABC to judges at size AB BC and AC at point D E and F respectively if AB =12 BC=8 AC=10 then find the length of AD BF and CF

Posted by Neha Rawat 3 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Navya Bhatia 3 years, 6 months ago

As AD = AF (tangents to the circle) similarly BD=BE AND CE=CF so let AD be x Then BD become 12-x and BE also become 12-x Then AF also becomes x and CF become 10-x and CE also 10-x Now, we will add 12-x+10-x and x = 22 So, AD =22 BE = 10 CF = 12

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