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Show that (a-b)², (a²+b²) , (a+b)² …

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Show that (a-b)², (a²+b²) , (a+b)² are in AP

    • Posted by Bhagya Sri 3 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Swati Suman 3 years, 6 months ago

    For being in AP common difference of successive terms of an AP be equal (a^2+b^2)-(a-b)^2=(a+b)^2-(a^2+b^2) LHS = (a^2+b^2)-(a-b)^2 = a^2+b^2-a^2-b^2+2ab =2ab RHS = (a+b)^2-(a^2+b^2) =a^2+b^2+2ab-a^2-b^2 =2ab Therefore, LHS=RHS Hence, the common difference among successive terms is equal . So, the given terms are in AP.

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