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The sum of digits of a …

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The sum of digits of a two digit number is 13. If the number is subtracted from the one obtained by interchanging the digits, the result is 45. What is the number?

Posted by Mahi Jain 3 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Kartik Chilkoti 3 years, 7 months ago

the tens digit be x and ones digit be y Required digit =(10x+y) According to question X+y=13 eq first And (10x+y) - (10y+x)=45 10x +y - 10y- x =45 9x - 9y =45 9(x-y) =45 X- y=5 eq seccond eq first - eq second X+y =13 X-y = 5 2x=18 X=9 From eq first X+y=13 Y=13-9 Y=4 Hence, required digit =10×9+4 =94 Hope, it will help you ☺ Hence answer will be 94

Anisha Kumari 3 years, 7 months ago

Let the tens digit be x and ones digit be y Required digit =(10x+y) According to question X+y=13 eq first And (10x+y) - (10y+x)=45 10x +y - 10y- x =45 9x - 9y =45 9(x-y) =45 X- y=5 eq seccond eq first - eq second X+y =13 X-y = 5 2x=18 X=9 From eq first X+y=13 Y=13-9 Y=4 Hence, required digit =10×9+4 =94 Hope, it will help you ☺

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