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100g of ice at 0°C is …

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100g of ice at 0°C is mixed with 100g of water at 80°C
  • 1 answers

Preeti Dabral 2 years, 3 months ago

iceat0Cwaterat0Cwaterat6C

At equilibrium, heat released by 100gm of water = heat absorbed by 100gm of ice i.e.m1c1 (80 - 6) = m2 L + m2c1(6 - 0)[c1, m1, m2 and L are specific heat of water, mass of water, mass of ice and latent heat of fusion of ice respectively.)
100 × 1 × 74 = 100 L + 100 × 1 × 6

L = (1 × 74) -6
 L = 68 cal/gm

This is the required value of latent heat of fusion of ice.

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