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Universal low of gravitational

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Universal low of gravitational

    • Posted by Krishna Mishra 2 years, 7 months ago

    CBSE > Class 11 > Physics
    • 4 answers

    Madhu Dwivedi 2 years, 4 months ago

    F =g×m1m2w/r²

    0Thank You

    Deepak Kumar Meena 2 years, 6 months ago

    F = G M1. M2/r2 Two bodies is directly proportional to the mass of the object and inversely proportional to the distance between them. G = Universal Gravitational constant 6.67×10*11 n m square kilogram square. g= G me /r square g is acceleration due to gravity It's value maximum at pole minimum at equator that's why weight of the body at the centre of earth would be zero. 9.8m/sec *2 G is given by Henry Cavendish Three equation of motion under gravity V = u +gt H = ut +1/2 gt 2i V *2 = u *2 ×2 gh Motion in n second HN = u +1/2 a (2 n -1) Value of g will be positive incase of up to down motion

    0Thank You

    Pooja S 2 years, 7 months ago

    Every particles attracts every other particles in the universe with a force that is directly proportional to the product of there masses and inversely proportional to the square of the distance between their centers.

    0Thank You

    Abhinav Jha 2 years, 7 months ago

    G=m1+m2/r^2

    1Thank You

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