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find the value of k 2xsq+kx+3=0

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find the value of k 2xsq+kx+3=0

Posted by Fm Khan 3 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Mohit Nimje 3 years, 7 months ago

Discriminant = b^2-4ac We have, B=K, A=2, C=3. put this values on there places K^2-4x2x3=0 (Put this in equal to zero) K^2-24= 0 Take 8 other side of equal so it will be +24 K^2= 4 When we remove square from k on other side of equal root will charge K= √24 So are k will be K= 2√6 are final answer

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CBSE > Class 10 > Mathematics