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5x²+8x-4=0

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5x²+8x-4=0
  • 3 answers

Anurag Chaudhary 3 years, 7 months ago

5x²+8x-4=0 5x²+(10-2)x-4=0 5x²+10x-2x-4=0 5x(x+2)-2(x+2)=0 (5x-2)(x+2)=0 So, (x=⅖) & [x=(-2)]

Bhumika Goswami 3 years, 7 months ago

5x²+8x-4 5x²+(10-2)x-4 5x²+10x-2x-4 5x(x+2)-2(x+2) (x+2),(5x-2) x=-2,x=2/5

Ayushi Gupta 3 years, 7 months ago

5x2 + 8x - 4 = 0 5x2 + 10x - 2x - 4 =0 5x(x+2) -2(x+2) = 0 (5x-2) (x+2) = 0 X = -2, 2/5
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