A hydrogen atom in its ground …
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A hydrogen atom in its ground state is excited by means of monochromatic radiation of wavelength 975 Angstron.How many lines are possible in resulting emission spectrum?Calculate the longest wavelength among them. You may assume ionisation energy for hydrogen atom as 13.6eV.
Posted by Parth Makhija 2 years, 6 months ago
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Preeti Dabral 2 years, 6 months ago
The wavelength of the incident radiation, λ = 975 oA
∴ The energy of the incident photon = hc/λ
= 6.63×10−34×3×108975×10−10×1.6×10−19 = 12.75 eV
Let electron is exerted to nth orbit,
⇒ 12.75 = 13.6 (112−1n2)
⇒ n = 4
The quantum transitions to the less excited states gives six possible lines as follows:
n = 4 : (4 → 3), (4 → 2), (4 → 1)
n = 3 : (3 → 2), (3 → 1)
n = 2 : (2 → 1)
Emin = (E4 - E3) = 13.6 (132−142) = 0.661 eV
Thus λmax=hcEmin
= 6.63×10−34×3×1080.661×1.6×10−19m
≈ 18807 oA
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