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A hydrogen atom in its ground …

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A hydrogen atom in its ground state is excited by means of monochromatic radiation of wavelength 975 Angstron.How many lines are possible in resulting emission spectrum?Calculate the longest wavelength among them. You may assume ionisation energy for hydrogen atom as 13.6eV.
  • 1 answers

Preeti Dabral 2 years, 6 months ago

  1. Energy of the ground state (n = 1) = – (ionization energy) = –13.6 eV
    The wavelength of the incident radiation, λ = 975 oA
     The energy of the incident photon = hc/λ 
    6.63×1034×3×108975×1010×1.6×1019 = 12.75 eV
    Let electron is exerted to nth orbit,
     12.75 = 13.6 (1121n2)
     n = 4
    The quantum transitions to the less excited states gives six possible lines as follows:
    n = 4 : (4  3), (4  2), (4  1)
    n = 3 : (3  2), (3  1)
    n = 2 : (2  1)
  2. The longest wavelength emitted is for the transitions (4  3) where energy difference is minimum.
    Emin = (E4 - E3) = 13.6 (132142) = 0.661 eV
    Thus λmax=hcEmin
    6.63×1034×3×1080.661×1.6×1019m
     18807 oA
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