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Check whether the following is a equation or not. (x²+1)(x+1)= (x+3)²
  • 2 answers

Neelam Kumari 3 years, 10 months ago

X(x²+1)+1(x²+1) =||+X³+X+x²+1=(x+3)² =||As it is=x²+3³+2(x)(3) =|| ""=X²+9+6x X³+X+x²+1==X²+9+6x{x² cancel by x²}__{+1-9=-8}_{x-6x=-5x} Then the left equation will be X³-5x-8=0 And degree of equations is highest power of equations And here the highest power is 3 ,so it is cubic equations not quadratic equations

Paras Yadav 3 years, 10 months ago

No, because xcube -5x -8
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