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Factorise using factor theorem x³-3x²-10x+24

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Factorise using factor theorem x³-3x²-10x+24

    • Posted by Arnav Gupta 2 years, 9 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Himanshi Choudhary 2 years, 9 months ago

    Hi, Factors of x³-3x²-10x+24 Factors of x³-3x²-10x+24= (x-2)(x-4)(x+3) Step-by-step explanation: Let the polyomial p(x)=x³-3x²-10x+24 = x³+(-2x²-x²)+(2x-12x)+24 =(x³-2x²)+(-x²+2x)+(-12x+24) =x²(x-2)-x(x-2)-12(x-2) =(x-2)(x²-x-12) =(x-2)(x²-4x+3x-12) =(x-2)[x(x-4)+3(x-4)] =(x-2)[(x-4)(x+3)] =(x-2) (x-4) (x+3) Therefore, Factors of x³-3x²-10x+24 = (x-2)(x-4)(x+3) Hope this help you!! Thankyou

    0Thank You

    Piyush ❤️ 2 years, 9 months ago

    Hm

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