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A raindrop of mass 2.00 g …

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A raindrop of mass 2.00 g falls from a height of 1.00 km. It hits the ground with a speed of 50.0 m/s. What is the work done by the resistive forces if any? (Take g = 10 ms 2)
  • 1 answers

Vasudha Vasudha 2 years, 11 months ago

Assuming u=0 and constant g=10ms−2 the work done by the grativational force is Wg=mgh =2×10−3×10×103=20J (b) ΔK=12mV2−0 =12×2×10−3×40×40 =1.6J From the work-energy theorem Δk=Wg+Wr where Wr is the work done by the opposing resistive force. 1.6=20+Wr Wr=−18.4J
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