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sin^2 + sin^2 A tan^2 A

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sin^2 + sin^2 A tan^2 A
  • 2 answers

[Vishal Kumar Paswan] [11] 4 years, 1 month ago

sin²A + sin²A*tan²A = sin²A(1+tan²A) = sin²A*sec²A = (sin²A)/(cos²A) = tan²A

Karamjitsidhu Karamjit Singh 4 years, 1 month ago

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