The volume of right circular cone …
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Rajeev Malhotra 8 years, 4 months ago
volume of cone = π{tex}r^2h/3{/tex}
{tex}πr^2h/3{/tex} = 9856
616xh/3 = 9856
h= 9856 x3/616
h = 16 x3
h =48 cm
{tex}πr^2 = 616{/tex}
{tex}22. r^2/7 =616{/tex}
{tex}r^2 {/tex} = 616 x7 /22
{tex}r^2{/tex} = 28 x7
r = 14 cm
{tex}slant height l = (h^2 + r^2)^1/2{/tex}
{tex}l = (14^2 + 48^2)^1/2{/tex}
{tex}l= (196+2304)^1/2{/tex}
{tex}l = (2500)^1/2{/tex}
l = 50 cm
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