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If 2x+y=23 and 4x-y=19 then the value of (5y-3x) and (y/x-2) are:

Posted by Kunal Kumar 3 years, 11 months ago

CBSE > Class 10 > Mathematics

3 answers

Tapasya !! 3 years, 11 months ago

By elimination method we have: 2x + y = 23 ...?➡️ 4x - y = 19 ...?➡️ ➡️ 6x = 42 ....? ➡️➡️➡️ From eq.3 we have x = 7 On substituting value of x in any of the eq: (let be in eq.2) 2x + y = 23➡️ {We know, x=7} 2(7)+y = 23➡️ 14+y = 23➡️ y = 23-14➡️ y = 9➡️➡️➡️ Now, we have values of both x and y {x=7; y=9}➡️➡️➡️ Final ques➡️ Find value of (5y-3x) and (y/x-2)➡️➡️➡️ Part-1➡️ 5y-3x {x=7; y=9}➡️ 5(9)-3(7)➡️ 45-21➡️ Ans [24]➡️ ➡️➡️➡️ Part-2➡️ y/x -2 {x=7; y=9)➡️ 9/7 -2➡️ 9/7 -14/7➡️ Ans [-5/7]➡️

1Thank You

Tapasya !! 3 years, 11 months ago

By elimination method we have: 2x + y = 23 ...?➡️ 4x - y = 19 ...?➡️ ➡️ 6x = 42 ....?➡️➡️➡️➡️➡️➡️From eq.? we have x = 7➡️➡️➡️➡️➡️➡️➡️ On substituting value of x in any of the eq: (let be in eq.?) ➡️➡️➡️➡️➡️➡️ 2x + y = 23 {We know, x=7} 2(7)+y = 23 14+y = 23 y = 23-14 y = 9 ➡️➡️➡️➡️➡️➡️ Now, we have values of both x and y {x=7; y=9} ➡️➡️➡️➡️➡️➡️ Final ques Find value of (5y-3x) and (y/x-2) ➡️➡️➡️➡️➡️➡️ Part-1 5y-3x {x=7; y=9} 5(9)-3(7) 45-21 Ans [24] ➡️➡️➡️➡️➡️➡️ Part-2 y/x -2 {x=7; y=9) 9/7 -2 9/7 -14/7 Ans [-5/7]

1Thank You

Tapasya !! 3 years, 11 months ago

By elimination method we have: 2x + y = 23 ...1 4x - y = 19 ...2 ➡️ 6x = 42 ....3 From eq.3 we have x = 7 On substituting value of x in any of the eq: (let be in eq.2) 2x + y = 23 {We know, x=7} 2(7)+y = 23 14+y = 23 y = 23-14 y = 9 Now, we have values of both x and y {x=7; y=9} Final ques Find value of (5y-3x) and (y/x-2) Part-1 5y-3x {x=7; y=9} 5(9)-3(7) 45-21 Ans [24] Part-2 y/x -2 {x=7; y=9) 9/7 -2 9/7 -14/7 Ans [-5/7]

1Thank You

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