The perimeter of rhombus is 20cm. …

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Given perimeter =20cm Hence each side =20/4=5cm Let ABCD be a rhombus where AC and BD are diagonals There in ∆ABC area is : {AB+BC+CA=5+5+6=16 Hence semiperimeter is 16/2=8cm} Now using Hero's Formulas: →√{s(s-a)(s-b)(s-c)} →√{8(8-5)(8-5)(8-6)} →√(8*3*3*2) →√(16*9) →√144 →12cm² Since area of rhombus is 2 times the area of triangle 2*12cm² 24cm². Hence the area of rhombus is 24cm² when its perimeter is 20cm and one of its diagonal is 6cm Thanks...... [Tip : Always draw a diagram of geometrical problems whether finding area or solving problems in geometrical,,,,] PARAM SIDHU

Given perimeter =20cm Hence each side =20/4=5cm Let ABCD be a rhombus where AC and BD are diagonals There in ∆ABC area is : {AB+BC+CA=5+5+6=16 Hence semiperimeter is 16/2=8cm} Now using Hero's Formulas: √{s(s-a)(s-b)(s-c)} √{8(8-5)(8-5)(8-6)} √(8*3*3*2) √(16*9) √144 12cm² Since area of rhombus is 2 times the area of triangle 2*12cm² 24cm² Hence the area of rhombus is 24cm² when its perimeter is 20cm and one of its diagonal is 6cm Thanks...... [Tip : Always draw a diagram of geometrical problems whether finding area or solving problems in geometrical,,,,] PARAM SIDHU(name)