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Show that the sum of all …

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Show that the sum of all odd integers between 1 and 1000 which are divisible by 3 is 83667.

    • Posted by Piyush Ranjan 3 years ago

    CBSE > Class 11 > Mathematics
    • 2 answers

    Harmanpreet Kaur 3 years ago

    Here,first term =3 and last term=999. It is an ap-3,9,15,21......... Common difference =6 999=3+(n-1)6 996/6=n-1 166+1=n n=167 Now sum of terms is given by- Snth=n/2(2a+(n-1)d) 167/2(2×3+166×6) 167/2(1002) =83667 L.H.S=R.H.S Hence proved

    1Thank You

    Sarika Parjapat 3 years ago

    ?ᴅᴏɴᴛ ᴋɴᴏᴡ

    1Thank You

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