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A ball is kicked at an …

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A ball is kicked at an angle of 35° with the ground. a.. What should be the initial velocity of the ball so that it hits a target that is 30metre away at a height of 1.8meter ? b... What is the time for the ball to reach the target?
  • 1 answers
Answer: hola mate here is ur answer a) x = V0 cos(35°) t 30 = V0 cos(35°) t t = 30 / V0 cos(35°) 1.8 = -(1/2) 9.8 (30 / V0 cos(35°))2 + V0 sin(35°)(30 / V0cos(35°)) V0 cos(35°) = 30 √ [ 9.8 / 2(30 tan(35°)-1.8) ] V0 = 18.3 m/s b) t = x / V0 cos(35°) = 2.0 s tq♥️
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