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ABCD is a parallelogram. AP is …

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ABCD is a parallelogram. AP is the bisector of angle A meeting BC at P and P is the mid point of BC then prove that AD =2XCD
  • 1 answers

Chahak Chandani 2 years, 11 months ago

Can you please provide the diagram so I can try and help you
http://mycbseguide.com/examin8/

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