What is the value of tan …
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Posted by Jagdish Verma 8 years, 4 months ago
- 1 answers
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Dharmendra Kumar 8 years, 4 months ago
We can find its value as follows:-
tan15°= tan(45°-30°)
= {tex}{tan 45° - tan30°\over 1+tan45°tan30°}{/tex}
= {tex}{1- {1\over {\sqrt 3}}}\over1+1×{1\over {\sqrt 3}}{/tex}
= {tex}{{{\sqrt 3}-1}\over {\sqrt 3}}\over {{{\sqrt 3}+1}\over {\sqrt 3}}{/tex}
= {tex}{\sqrt 3}-1\over {\sqrt 3}+1{/tex}
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