In a figure if angle x …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Kamiya Shah 4 years, 3 months ago
- 1 answers
Related Questions
Posted by Sheikh Alfaz 3 months, 2 weeks ago
- 0 answers
Posted by Yash Pandey 8 months ago
- 0 answers
Posted by Alvin Thomas 4 months, 4 weeks ago
- 0 answers
Posted by Duruvan Sivan 8 months ago
- 0 answers
Posted by Savitha Savitha 1 year, 6 months ago
- 0 answers
Posted by Akhilesh Patidar 1 year, 6 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 4 years, 3 months ago
Consider the triangles AEB and CDB
{tex}\angle{/tex}EBA = {tex}\angle{/tex}DBC ... (Common angle) ... (i)
Further, we have:
{tex}\angle{/tex}BEA = 180 - y
{tex}\angle{/tex}BDC = 180 - x
Since x = y, we have:
180 - x = 180 - y
{tex}\angle{/tex}BEA = {tex}\angle{/tex}BDC ... (ii)
AB = CB ... (Given) ... (iii)
From (i), (ii) and (iii), we have:
{tex}\triangle{/tex}BDC{tex}\cong{/tex}{tex}\triangle{/tex}BEA ... (AAS criterion)
{tex}\therefore{/tex} AE = CD (CPCT)
Hence, proved.
0Thank You