
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by 🤟Royal Thakur 🤟 4 years, 1 month ago
- 4 answers
Aseem Mahajan 4 years, 1 month ago
B at centre of a ring = $$\dfrac{\mu_0I}{2R}$$
I = $$\dfrac{q}{T}=qf$$
Thus, B = $$\dfrac{\mu_0qf}{2R}$$
I = $$\dfrac{q}{T}=qf$$
Thus, B = $$\dfrac{\mu_0qf}{2R}$$
Related Questions
Posted by Anterpreet Kaur 1 year, 5 months ago
- 0 answers
Posted by Aniket Mahajan 10 months ago
- 0 answers
Posted by Khushbu Otti 1 year, 5 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
</a>

Aseem Mahajan 4 years, 1 month ago
1Thank You