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Posted by 🤟Royal Thakur 🤟 3 years, 11 months ago
- 4 answers
Aseem Mahajan 3 years, 11 months ago
B at centre of a ring = $$\dfrac{\mu_0I}{2R}$$
I = $$\dfrac{q}{T}=qf$$
Thus, B = $$\dfrac{\mu_0qf}{2R}$$
I = $$\dfrac{q}{T}=qf$$
Thus, B = $$\dfrac{\mu_0qf}{2R}$$
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Aseem Mahajan 3 years, 11 months ago
1Thank You