3/13÷(-4/65)

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Sia ? 4 years ago
Here, {tex}\frac {3}{13} \div \frac {-4}{65}{/tex}
= {tex}\frac {3}{13} \times \frac {65}{-4}{/tex}
= {tex}\frac {65 \times 3}{13 \times (-4)}{/tex}
= {tex}\frac {15}{-4}{/tex}
Therefore, the reciprocal is {tex}\frac {-4}{15}{/tex}
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