A contractor plans to install two …
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Sia ? 4 years ago
In the first case:
Height of slide= 1.5 m and angle of elevation = 30°
Now,
{tex}\sin \theta=\frac{p}{h}{/tex}
where p = perpendicular, i.e. height of the slide and h = hypotenuse, i.e. length of the slide and {tex}\theta{/tex} is the angle of elevation
{tex}\sin 30^{\circ}=\frac{1.5}{h}{/tex}
{tex}\frac{1}{2}=\frac{1.5}{h}{/tex}
Hence, h = 3 m
In the second case:
Height of slide, = 3 m, angle of elevation = 60°
{tex}\sin \theta=\frac{p}{h}{/tex}
{tex}\sin 60^{\circ}=\frac{3}{h}{/tex}
{tex}\frac{\sqrt{3}}{2}=\frac{3}{h}{/tex}
Hence, h = {tex}2{\sqrt{3}}{/tex} m
Therefore, the length of the slide in the first and the second case are 3 m and {tex}2{\sqrt{3}}{/tex} m respectively.
2Thank You